Examples
1) The scale of an aerial
photograph is 1 cm = 100 m. The photograph size is 20cm x 20cm. Determine the
number of photographs required to cover an area of 100 sq. km if the
longitudinal lap is 60% and the side lap is 30%.
photograph is 1 cm = 100 m. The photograph size is 20cm x 20cm. Determine the
number of photographs required to cover an area of 100 sq. km if the
longitudinal lap is 60% and the side lap is 30%.
Solution.
Here l = 20
cm ;
w = 20 cm ; P1 = 0.60 ; Pw = 0.30
cm ;
w = 20 cm ; P1 = 0.60 ; Pw = 0.30
length covered by each photograph is
L = (1 – Pl) sl = (1-
0.6) 100 x 20 = 800 m = 0.8 km
0.6) 100 x 20 = 800 m = 0.8 km
Actual ground width covered by
each photograph is
each photograph is
W = (1 – Pw) sw = (1 – 0.3) 100 x 20 = 1400 m = 1.4 km
covered by each photograph is
a = L
x W = 0.8 x 1.4 = 1.12 sq. km
x W = 0.8 x 1.4 = 1.12 sq. km
hence number of photographs
required is
required is
2) The scale of an aerial
photograph is 1cm = 100 m. The photograph size is 20cm x 20xm. Determine the
number of photograph required to cover an area 10 km x 10km, if the
longitudinal lap is 60% and the side lap is 30%.
photograph is 1cm = 100 m. The photograph size is 20cm x 20xm. Determine the
number of photograph required to cover an area 10 km x 10km, if the
longitudinal lap is 60% and the side lap is 30%.
Solution
Here L1
= 10 km ; L2 = 10 km
= 10 km ; L2 = 10 km
in each strip is given by
Number of flight lines required
is given by
is given by
Hence number of photographs
required will be
required will be
The spacing of the flight lines
would be 10/9 = 1.11 km and not 1.4 as calculated theoretically in the previous
example.
would be 10/9 = 1.11 km and not 1.4 as calculated theoretically in the previous
example.
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